Question

A racing car has a uniform acceleration of 4 m s-². What distance will it cover in 10 s after start ?

Answer 1

Answer:200m

Explanation:

Using this equation of motion.

S=ut +1/2at^2

S=0(10)+ 4(10)^2/2

=4*100/2

=400/2

S=200m

Answer 2

Answer:

200 metres

Explanation:

Given :

Initial velocity = u = 0 m/s

Acceleration = a = 4 m/s²

Time taken = t = 10 seconds

To find :

Distance covered by the racing car after the start

Using the second equation of motion :

S=u×t+½×at²

S=0×10+½×4×10²

S=0+2×100

S=2×100

S=200 metres

The distance covered by the racing car after its start is equal to 200 metres

Extra dose:

First equation of motion : V=u+at

Third equation of motion : V²-u²=2as

So the answer is 200 metres