Question

A RACING CAR HAS A UNIFORM ACCELERATION OF 4 M/S2 . WHAT DISTANCE WILL IT COVER IN 10 SECOND AFTER THE START

Answer 1

Given :

• Acceleration(a) = 4m/s²

• Time(t) = 10 seconds

• Initial speed(u) = 0 m/s

To Find :

• Distance Covered

Solution :

Let's Find Final Velocity(v) from the First Equation of Motion :

★ v = u + at

→ v = 0 + 4 × 10

→ v = 0 + 40

→ v = 40 m/s

Now, Let's find the distance covered using second equation of motion :

★ s = ut + ½ at²

→ s = (0)(10) + ½ (4)(10)(10)

→ s = 0 + ½ × 400

→ s = $\sf\cancel\dfrac{400}{2}$

→ s = 200 m

$\therefore$ Total distance covered by the car after 10 seconds is 200 m

Note - Symbols have their usual meaning.

Here,

• u = Initial Velocity

• v = Final Velocity

• t = Time taken

• s = Distance covered

• a = acceleration produced

Answer 2

Aɴꜱᴡᴇʀ

☞ Distance travelled is equal to 200 m

_________________

Gɪᴠᴇɴ

➳ Acceleration (a) = 4m/s²

➳ Initial velocity (u) = 0 m/s

➳ Time (t) = 10 seconds

_________________

Tᴏ ꜰɪɴᴅ

➤ Distance covered?

_________________

Sᴛᴇᴘꜱ

❍ As we have the acceleration, the initial velocity (we assume it) and the time taken.

✭ So the distance travelled is given by,

$\large { \underline{ \boxed{ \sf{s = ut + \frac{1}{2} \: a {t}^{2} }}}}$

Substituting the given values,

$\large \tt \dashrightarrow{}s = 0 \times 10 + \frac{1}{ \cancel2} \times \cancel4 \times {10}^{2} \\ \\ \large \tt \dashrightarrow{}s = 2 \times 100 \\ \\ \large \tt { \pink{\dashrightarrow{}s = 200 \: m}}$

______________________