Physics, asked by natht8862, 9 months ago

A racing car has a uniform acceleration of 4 m/s². What distance will it cover in 10 seconds after the start from the rest ?​

Answers

Answered by dipamcool2016
1

Answer:

Given,

Acceleration (a) = 4 m/s^2

Time (t) = 10 s

Initial Velocity (u) = 0 m/s

Let the Distance be denoted as S.

S = 1/2ut+at^2

= at^2

= 4*10*10

= 400 m

I hope this helps.

Answered by Anonymous
1

Answer:

\mathfrak{\underline{AnswEr:-}}

The distance covered by racing car = 200m

{\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}

\mathfrak{\underline{Given:-}}

⟶ Given initial velocity is 0

⟶ Given acceleration is 4m/s²

⟶ Given time taken is 10 seconds

\mathfrak{\underline{Need\:To\: Find:-}}

The distance covered by racing car = ?

{\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}

By the second equation of motion,

\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}

\bigstar{\underline{\boxed{\sf\purple{s = ut + \dfrac{1}{2} at^2}}}} \\\\

\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}

\longrightarrow \sf {s = 0 \times 10 + \dfrac{1}{2} × 4 × 10 × 10}\\\\

\longrightarrow \sf {s = 0 + 2 \times 100} \\\\

\longrightarrow\large\boxed{\sf{\purple{s\:=\:200\:m}}}\\\\

\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}

The distance covered by racing car is 200m.

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