Question

A racing car has a uniform acceleration of 4 m square what distance will it cover in 10 second after start​

Answer 1

Acceleration = 4m/s

Time (t)= 10s

Distance (s) = ?

Initial velocity (u) =0

Using second equation of motion

S = ut+ 1/2 at²

S = 0×10 + 1/2× 4× (10)²

S= 0 + 1/2×4× 10 × 10

S= 1/2× 400

S = 200m.

HOPE THIS HELPS U

MARK ME AS BRAINLIEST AND FOLLOW ME

THANK YOU

Answer 2

Answer:

$\mathfrak{\underline{AnswEr:-}}$

The distance covered by racing car = 200m

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{Given:-}}$

⟶ Given initial velocity is 0

⟶ Given acceleration is 4m/s²

⟶ Given time taken is 10 seconds

$\mathfrak{\underline{Need\:To\: Find:-}}$

The distance covered by racing car = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

By the second equation of motion,

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\bigstar{\underline{\boxed{\sf\purple{s = ut + \dfrac{1}{2} at^2}}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {s = 0 \times 10 + \dfrac{1}{2} × 4 × 10 × 10}$

$\longrightarrow \sf {s = 0 + 2 \times 100}$

$\longrightarrow\large\boxed{\sf{\purple{s\:=\:200\:m}}}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

The distance covered by racing car is 200m.