Question

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?​

Answer 1

Answer:

s =ut +1/2 at^2

Explanation:

uis 0; and by applying fornula we get d = 80 m

Answer 2

Answer:

200 metres

Explanation:

Given:

• Initial velocity = u = 0 m/s
• Acceleration = a = 4 m/s²
• Time taken = 10 seconds

To find:

• Distance it will cover in 10 seconds after start

First using first equation of motion:

V=u+at

V=0+4×10

V=0+40

V=40 m/s

Now using third equation of motion:

V²-u²=2as

40²-0²=2×4×s

1600-0=8s

1600=8s

s = $\frac{1600}{8}$

s = 200 metres

The distance covered by the racing car after start is equal to 200 metres