A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?
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Only put the values and use second equation of motion.
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200 metres
Explanation:
Given:
Initial velocity = u = 0 m/s
Acceleration = a = 4 m/s²
Time taken = 10 seconds
To find:
Distance it will cover in 10 seconds after start
First using first equation of motion:
V=u+at
V=0+4×10
V=0+40
V=40 m/s
Now using third equation of motion:
V²-u²=2as
40²-0²=2×4×s
1600-0=8s
1600=8s
s = 1600/8
s = 200 metres
The distance covered by the racing car after start is equal to 200 metres
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