Physics, asked by XxpriyanshuxX, 10 months ago

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?

Answers

Answered by DelhiQueen

Answer:

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200 metres

Explanation:

Given:

Initial velocity = u = 0 m/s

Acceleration = a = 4 m/s²

Time taken = 10 seconds

To find:

Distance it will cover in 10 seconds after start

First using first equation of motion:

V=u+at

V=0+4×10

V=0+40

V=40 m/s

Now using third equation of motion:

V²-u²=2as

40²-0²=2×4×s

1600-0=8s

1600=8s

s = 1600/8

s = 200 metres

The distance covered by the racing car after start is equal to 200 metres

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Answered by Anonymous

Explanation:

given :-

initial velocity = u = 0m/s

acceleration = 4m/s²

time = t = 10 seconds

by third equation of motion we get,

➡ s = ut + 1/2 at²

therefore the distance covered by the car after 10 seconds = ut + 1/2 at²

= (0 × 10) + 1/2 × 4 × (10)²

= 2 × 100

= 200m

hence, the distance covered by the racing car after 10 seconds is 200m.

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200 metres

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?