Physics, asked by XxpriyanshuxX, 10 months ago

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?

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Answered by DelhiQueen

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200 metres

Explanation:

Given:

Initial velocity = u = 0 m/s

Acceleration = a = 4 m/s²

Time taken = 10 seconds

To find:

Distance it will cover in 10 seconds after start

First using first equation of motion:

V=u+at

V=0+4×10

V=0+40

V=40 m/s

Now using third equation of motion:

V²-u²=2as

40²-0²=2×4×s

1600-0=8s

1600=8s

s = 1600/8

s = 200 metres

The distance covered by the racing car after start is equal to 200 metres

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Answered by Anonymous

Answer:

a = 4m/s^2

u = 0m/s

t = 10s

s = ?

s = ut + 1/2 at^2

s = 0m/s * 10s + 1/2 * 4m/s^2 * ( 10s )^2

s = 1/2 * 4m/s^2 * 100s^2

s = 200m

hope it helps

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A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?​

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A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?