Question

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?​

Answer 1

Answer:

Distance covered till 10th s is 200 m

Distance  covered in 10th s is 38 m

Explanation:

 Let the initial velocity be u.

Using the equations of motion :

          S = ut + (1/2)at^2

 Distance covered in 10 second is :

   S = u( 10 ) + (1/2)(4)(10)^2  m

      = 10u + 2(100) m

      = 10u + 200 m

Distance  covered in 9 second is :

   = u( 10 ) + (1/2)(4)(9)^2 m

   = 10u + 2(81) m

   = 10u + 162

 

Distance covered in 10th second :

 distance till 10 sec - distance till 9 sec

= 10u + 200 - ( 10u + 162 ) m

= 200 - 162 m

= 38 m

Answer 2

$\underline{\underline{\huge{\red{\mathfrak{Answer}}}}}$

$\bf{\orange{Given:}}$

Initial velcoity (u) = 0 m/s

Time (t) =10 sec

uniform acceleration (a) =4m/s²

$\bf{\green{To \: Find:}}$

Distance (s) =?

$\bf{\blue{Solution:}}$

From Newton's 2ⁿᵈ equation of motion:

s=ut+1/2at²

=0x10+1/2x4x(10)²

=2x100

=200m.

∴Distance it will cover in 10sec after start is 200m.

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