A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?
Answers
Answer:
200 metres
Explanation:
Given:
Initial velocity = u = 0 m/s
Acceleration = a = 4 m/s²
Time taken = 10 seconds
To find:
Distance it will cover in 10 seconds after start
First using first equation of motion:
V=u+at
V=0+4×10
V=0+40
V=40 m/s
Now using third equation of motion:
V²-u²=2as
40²-0²=2×4×s
1600-0=8s
1600=8s
s = 1600/8
s = 200 metres
The distance covered by the racing car after start is equal to 200 metres
Question :-
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.➜Time taken (t)=10s
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.➜Time taken (t)=10sWe have to find the distance cover by car after 10s=???
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.➜Time taken (t)=10sWe have to find the distance cover by car after 10s=???Distance (s) =??
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.➜Time taken (t)=10sWe have to find the distance cover by car after 10s=???Distance (s) =??Solutions:-
Question :-➜A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start ?Given :-➜Initial velocity (u)=0m/s➜Acceleration(a)=4 metre per second square.➜Time taken (t)=10sWe have to find the distance cover by car after 10s=???Distance (s) =??Solutions:-➜By using Second equation of motion
S=ut+1/2 at sq.
S=0×10+1/2×4×10×10
s=200m
s=200m
s=200m
s=200m Hence the required answer is 200m