Physics, asked by XxpriyanshuxX, 10 months ago

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?

Answers

Answered by DelhiQueen

Answer:

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200 metres

Explanation:

Given:

Initial velocity = u = 0 m/s

Acceleration = a = 4 m/s²

Time taken = 10 seconds

To find:

Distance it will cover in 10 seconds after start

First using first equation of motion:

V=u+at

V=0+4×10

V=0+40

V=40 m/s

Now using third equation of motion:

V²-u²=2as

40²-0²=2×4×s

1600-0=8s

1600=8s

s = 1600/8

s = 200 metres

The distance covered by the racing car after start is equal to 200 metres

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Answered by kanekeikenghoul

Answer:

200 m

Explanation:

Given to us,

Uniform acceleration a = 4 m/s²

Initial velocity u= 0 m/s

Time t = 10 sec.

According to formula:

Velocity v after 10 sec

= u + a × t

= 0 m/s + 4 m/s² × 10 s

= 40 m/s.

Using Average Velocity:

Initial velocity u= 0 m/s

Final velocity v= 40 m/s

Average velocity= ½( u +v)

= ½ × (0+40)

= 20 m/s

Time= 10 s

We know,

u = 0 m/s

a = 4 m/s²

t= 10 sec.

Using the formula:

[s = u t+ ½ a × t²]

s = 0×10 + ½ 4 × 10² = 200 m

We know:

u = 0 m/s

v= 40 m/s

a= 4 m/s²

Using the formula:

[v² - u² = 2 a × s]

s = 1/2 a ( v² - u²)

= 1/2×4 ( 40² - 0²)

= 1/8(1600–0)

= 1600/8

= 200 m.

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200 metres

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?