Physics, asked by XxpriyanshuxX, 8 months ago

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?.

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Answered by DelhiQueen

Answer:

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200 metres

Explanation:

Given:

Initial velocity = u = 0 m/s

Acceleration = a = 4 m/s²

Time taken = 10 seconds

To find:

Distance it will cover in 10 seconds after start

First using first equation of motion:

V=u+at

V=0+4×10

V=0+40

V=40 m/s

Now using third equation of motion:

V²-u²=2as

40²-0²=2×4×s

1600-0=8s

1600=8s

s = 1600/8

s = 200 metres

The distance covered by the racing car after start is equal to 200 metres

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Answered by Nachiketman

Answer: 200 m

Explanation:

s = ut + (1/2) a t²

t = 10 s

a = 4 m /s²

u = 0 (it starts from rest )

s = 0 + (1/2) 4 (10)(10)

s = 200 m

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A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?​.​

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200 metres

A racing car has a uniform acceleration of 4 metre per second square.What distance will it cover in 10 s after start?.