Question

a racing car has a uniform acceleration of 4 metre per second ^2 the distance covered by the car in 10 second after the start is

Answer 1

let u=0
t=10s
a=4m/s²
S=?

S=ut+(1/2)at²
=0×10+(1/2)4×10²
=0+200
=200mtr

Answer 2

Initial velocity (u) = 0 ms-1
Time (t) = 10 s
Acceleration (a) = 4 m/s^2

Distance (s) = ?

Now,

s = ut + 1/2 at^2
s = 0*10 + 1/2*4*(10)^2
s = 0 + 2*100
s = 200 metres.

Distance = 200 m