A racing car has a uniform acceleration of 4 metre per second squared what distance will it cover in 10 sac after the start
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Heya!!
given,
a = 4 m/s² u= 0 m/sTime t = 10 sFinal velocity v= initial velocity (v) after 10 s = u + a t = 0 + (4 × 10) =40 m/s.U know the formula : v² - u² = 2 a s,s = 1/2 a ( v² - u²) = 1/2×4 ( 40² - 0²) = 1/8(1600–0) = 1600/8
given,
a = 4 m/s² u= 0 m/sTime t = 10 sFinal velocity v= initial velocity (v) after 10 s = u + a t = 0 + (4 × 10) =40 m/s.U know the formula : v² - u² = 2 a s,s = 1/2 a ( v² - u²) = 1/2×4 ( 40² - 0²) = 1/8(1600–0) = 1600/8
= 200 m.
hope this helps u friend:)))))))
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