Question

a racing car has a uniform acceleration of 4 ms². what distance will it cover in 10 sec after the starts ?

Answer 1

given that,

a = 4ms2.
t = 10sec.
u = 0.

using the second equation of motion,

s= ut + 1/2at*2

s = 1/2 × 4 ×(100)

s= 200m.
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Answer 2

a = 4 ms^-2

t = 10 s

u = 0

s = ?

Using 2nd Equation of Motion

${\implies s = ut + \dfrac{1}{2}at^{2}}$

${\implies s = 0\times 10 + \dfrac{1}{2}\times 4\times 100}$

= 0 + 200

= 200 m