Physics, asked by Krishna7777777, 11 months ago

A racing car has a uniform acceleration of 4m/s square the distance covered by the car in 10 seconds after the start

Answers

Answered by ShibShankar888
5

s = ut + 1/2 at²

s= 0+ 1/2 ×4 ×100 (since u= 0 )

s= 200

thus the car covers 200 m

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Answered by Anonymous
177

\huge\star\:\:{\orange{\underline{\purple{\mathcal{Solution}}}}}

Acceleration = \:\sf{4\: \dfrac{m}{s}^{2}}\:

Initial velocity = \:\sf{0\: \dfrac{m}{s}}\:

Time = \:\sf{10s}\:

\huge{\orange{\underline{\red{\mathscr{We\: know}}}}} :-

 \boxed {s \: = \: ut \: + \:  \dfrac{1}{2}{at}^{2}}

⟹ s = 0 × 10 +  \dfrac{1}{2} × 4 ×  {10m}^{2}

\text{⟹\:\:s\:\:=\:\:2\:\:×\:\:100m}

\text{⟹\:\:s\:\:=\:\:200m}

Thus racing car will cover a distance of 200m after start in 10s with given acceleration.

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