Question

a racing car has a uniform acceleration of 4m/s square .what distance will it cover in 10sec after start

Answer 1

here initial velocity=u
final velocity=v
acceleration=a
time=t

u=0
a=4
t=10
use the first equation of motion i.e -v=u+at

v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Answer 2

Given:
 Initial velcoity=u= 0 m/s
Time= t=10 sec
uniform acceleration=a=4m/s²
Distance =s=?
From second equation of motion:
S=ut+1/2at²
=0x10+1/2x4x[10]²
=2x100
=200m.
∴Distance it will cover in 10sec after start is 200m