Question

a racing car has a uniform acceleration of 4m/s square.what distance will it cover in 10 second​

Answer 1

Given :

• Acceleration is 4m/s²

• Time = 10 seconds

To Find :

• Distance covered

Solution :

It is in uniform acceleration,Initial Velocity (u) will be 0

From Second Equation of Motion :

$\bigstar \: \: \large \boxed{ \sf \: s = ut + \dfrac{1}{2} at ^{2} }$

Substituting the values :

$\longrightarrow \sf s = (0)(10) + \dfrac{1}{2} (4) ({10})^{2}$

$\longrightarrow \sf s = 0 + \dfrac{1}{2} \times 4 \times 10 \times 10$

$\longrightarrow \sf s = 0 + \cancel\dfrac{400}{2}$

$\longrightarrow \sf s = 0 + 200$

$\longrightarrow \red{ \sf s \: = 200 \: m}$

Here,

• s =distance covered

• u = initial velocity

• t = time taken

• a = acceleration produced

Answer 2

$\tt{\huge{\purple{ .............. }}}$

QUESTION :

a racing car has a uniform acceleration of 4m/s square.what distance will it cover in 10 second?

SOLUTION :

In the above Question, we have the following information given :

The acceleration of the racing car is 4 m / s ^ 2.

Let us assume the innitial velocity of the racing car as 0 m / s as the car is starting from rest.

So,

Using Newton's Second law of motion :

S = 1 / 2 a t ^ 2

S_10 = 200 m

S_9 = 162 m.

Distance travelled in 10 Seconds = S_10 - S _ 9 = 200 m - 162 m

=>38 m...... [ A ]