a racing car has a uniform acceleration of 4m/s² . what sidtance will it cover 10 seconds after the start
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Answered by
3
a = 4ms-2
t = 10s
s = ?
u = 0
s = ut + 1/2 at^2 = 0 × 10 +1/2×4×(10)^2
=0 +1/2 × 4×100
s = 200m
The distance covered in 10 s by the car is 200 m.
t = 10s
s = ?
u = 0
s = ut + 1/2 at^2 = 0 × 10 +1/2×4×(10)^2
=0 +1/2 × 4×100
s = 200m
The distance covered in 10 s by the car is 200 m.
Answered by
1
a = 4m/s^2
t = 10s
u= 0
v=?
s=?
v= u + at. first equation of motion
v= 0+ 4 × 10
v=40m/s
using third equation of motion
v^2- u^2= 2as
40^2=2(4)s
1600=8s
s=200m
t = 10s
u= 0
v=?
s=?
v= u + at. first equation of motion
v= 0+ 4 × 10
v=40m/s
using third equation of motion
v^2- u^2= 2as
40^2=2(4)s
1600=8s
s=200m
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