Question

a racing car has a uniform acceleration of 4m/s2.what distance will it cover in 10 seconds after the start ?​

Answer 1

Explanation:

Given that

The car is initially at rest;

initial velocity (u) = 0 ms-1

Acceleration (a) = 4 ms-2

Time period (t) = 10 s

Find out

What distance will it cover in 10 s after start

Formula

As per the second motion equation, s = ut+1/2 at2

Therefore, the total distance covered by the car (s) = 0 * 10m + 1/2 (4ms-2)(10s)2

= 200 meters

Therefore, the car will cover a distance of 200 meters after 10 seconds.

Answer 2

QUESTION

a racing car has a uniform acceleration of 4m/ s² what distance will it cover in 10 seconds after the start ?

SOLUTION

Given that

The car is initially at rest;

initial velocity (u) = 0 ms-1

Acceleration (a) = 4 ms²

Time period (t) = 10 s

Find out

What distance will it cover in 10 s after start

Formula

As per the second motion equation,

$s = ut + \frac{1}{2}at {}^{2}$

$s = 0 \times 10 + \frac{1}{2} \times 4 \times 10 {}^{2}$

$=0+200=200 m$

Therefore, the car will cover a distance of 200 meters after 10 seconds.