A racing car has a uniform acceleration of 4meters square.what distance will it cover in 10seconds after the start
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Answered by
22
As the racing car is starting , u = 0 m/s a = 4 m/s^2 Time, t =10 s As we know that S = ut + 1/2 at^2 So, distance covered in 10 s from start S = 0×10 + 1/2 × 4 × 10^2 = 0 + 200 =200 m so , it will cover a distance of 200 m in 10 s from start with a acceleration of 4 m/s^2.
Answered by
14
Heya.....
See here for the answer....
===========
Racing car is starting with...
u = 0 m/s
a = 4 m/s^2
time = 10s
As we know that.....
S= ut+1/2at^2 ...
So we may find distance covered by this....
S = 0*10+1/2*4*10^2
= 0+200 = 200 m
So ,, car will cover distance of 200 metre in 10 seconds with the acceleration of 4 m^2...
-- Be Brainly...
See here for the answer....
===========
Racing car is starting with...
u = 0 m/s
a = 4 m/s^2
time = 10s
As we know that.....
S= ut+1/2at^2 ...
So we may find distance covered by this....
S = 0*10+1/2*4*10^2
= 0+200 = 200 m
So ,, car will cover distance of 200 metre in 10 seconds with the acceleration of 4 m^2...
-- Be Brainly...
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