a racing car has a uniform acceleration of 4mls^2 the distance it covers in 10 seconds after the start is
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Explanation:
Given that
The car is initially at rest;
initial velocity (u) = 0 ms-1
Acceleration (a) = 4 ms-2
Time period (t) = 10 s
Find out
What distance will it cover in 10 s after start
Formula
As per the second motion equation, s = ut+1/2 at2
Therefore, the total distance covered by the car (s) = 0 * 10m + 1/2 (4ms-2)(10s)2
= 200 meters
Therefore, the car will cover a distance of 200 meters after 10 seconds.
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