Question

A racing car has a uniform acceleration of 4ms-2 what distance will it cover
in 10 seconds after the start

Answer 1

hey dear here is ur answer.......

Use 2nd eq.of motion i.e

S=ut+1/2at^2
S=1/2*4*10^2
S=200m .....


hope it might help u .....

Answer 2

if you use the relationship between distance and acceleration you will get the answer...let me do it for u.

s=ut+(1/2)at^2.
where s is distance
u is intial velocity
t is time
since a racing car starts from rest so it's initial velocity will be zero.

now

s=(1/2)at^2

now you knows everything in this equation isn't it.

you can get distance....

s=(1/2)(4)(100)
s=200 metre.

hope u get it