Question

A racing car has a uniform acceleration of 4ms^-2s. What distance will it cover in 10s after start?

Answer 1

solution

initial velocity, u= 0m/s

acceleration, a= 4ms^2/-2s

Given time= 10s

Using appropriate formula , s= ut+ 1/2 at^2

= 0*10+ 1/2 (4/2) 10^2

= 1* 100

= 100m

Answer 2

Answer:

Known Terms:-

u = Initial Velocity

a = Acceleration

t = Time

s = Distance

Given:-

Initial Velocity of  car, u = 0 ms-1

Acceleration of car, a = 4 m s-2

Time taken by the car, t = 10 s

To Find:-

Distance (s)

Solution:-

Here we have to find the distance

so,

we use 3rd equation of motion that is  s = ut + $\frac{1}{2}$at²

⇒ s = ut + $\frac{1}{2}$at²

⇒ s = 0 + ($\frac{1}{2}$) × 4 × 10²

⇒ s = 0 + ($\frac{1}{2}$) × 4 × 10 × 10

⇒ s = ($\frac{1}{2}$) × 400 m

⇒ s = 200 m

The distance cover in 10 s after start is 200 m.