Question

a racing car has a uniform acceleration of 5 ms-2 what distance will it cover in 20s after start​

Answer 1

Answer:

1 km or 1000 m

Explanation:

According to the given question,

a = acceleration = 5 m/s^2

t = time = 20 sec

u = initial velocity = 0 m/s

s = displacement

And we are asked to find distance.

Here, displacement can be treated as distance as it's linear motion, without change in direction.

Thus, s = distance/displacement

We know,

s = ut + 1/2 at^2

Putting the values we get,

s = 0 + 1/2 × 5 × 400

s = 5×200

s = 10,00 m

s = 1 km

Thus distance covered by the racing car in 20 sec is 1km or 1000 m when it's acceleration is 5 m/s^2 and starting from rest.

Explanation:

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Answer 2

Answer:

$\bigstar{\bold{Distance\:covered\:=\:1000\:m}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Acceleration (a) = 5 m/s²

• Time taken (t) = 20 s

• Initial velocity (u) = 0 m/s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

•   Distance covered by the car

$\Large{\underline{\underline{\bf{Solution:}}}}$

➙ By the second equation of motion,  

    s = ut + 1/2 × a × t²

➙ Substituting the given datas, we get  

     s = 0 × 20 + 1/2 × 5 × 20²    

     s = 1000 m

$\boxed{\bold{Distance\:covered\:=\:1000\:m}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

➙ The three equations of motion are:

• v = u + at

• s = ut + 1/2 × a × t²

• v² - u² = 2as

➙ Distance can also be found out by the formula  

    Distance = Speed × Time