A racing car has a uniform acceleration of 5m/s^2 what distance will it cover in 20s after starting for rest?
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Answered by
7
We have
u=O , a = 5m/s^2, t= 20s
By applying the formula
S = ut +1/2at^2
= 0 + 1/2 × 5 × 20×20
= 1000 m = 1 Km.
Hope this will help you.
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u=O , a = 5m/s^2, t= 20s
By applying the formula
S = ut +1/2at^2
= 0 + 1/2 × 5 × 20×20
= 1000 m = 1 Km.
Hope this will help you.
Pls mark this as brainliest.
Answered by
0
If s is the distance covered by the car then, s=ut + (1÷2)×f(t^2)
where, u is the initial speed , f is the acceleration and t is the time.
As the car start from rest u=0
so, s= 0+ (1÷2)×5×(20^2)
=1000 m
where, u is the initial speed , f is the acceleration and t is the time.
As the car start from rest u=0
so, s= 0+ (1÷2)×5×(20^2)
=1000 m
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