Question

A racing car has a uniform acceleration of 5m/s*s what distance will it cover in 20s after starting from rest

Answer 1

Answer:

1 km or 1000 m

Explanation:

According to the given question,

a = acceleration = 5 m/s^2

t = time = 20 sec

u = initial velocity = 0 m/s

s = displacement

And we are asked to find distance.

Here, displacement can be treated as distance as it's linear motion, without change in direction.

Thus, s = distance/displacement

We know,

• s = ut + 1/2 at^2

Putting the values we get,

• s = 0 + 1/2 × 5 × 400

• s = 5×200

• s = 10,00 m

• s = 1 km

Thus distance covered by the racing car in 20 sec is 1km or 1000 m when it's acceleration is 5 m/s^2 and starting from rest.

Answer 2

$\huge{\sf{===Answer===}}$

Initial Velocity (u) = 0

Acceleration (a) = 20 m/s²

Time (t) = 20 s

============================

We have formula :-

$\huge{\boxed{\boxed{\sf{S \: = \: ut \: + \: \frac{1}{2} \: at^2}}}}$

___________[Put Values]

S = 0(20) + 1(5)(20)²/2

S = 0 + 5(400)/2

S = 5(200)

S = 1000 m

$\huge{\boxed{\boxed{\sf{S \: = \: 1000 \: m}}}}$