Question

a racing car has a uniform acceleration of 5ms-^2. what distance will it cover in 20s after starting from rest?

Answer 1

Starting from rest means initial velocity u = 0

a= 5 m/s^2

t=20s

We know that

S=ut + 1/2 at^2

= 0+ 1/2 x 5 x 20 x 20

= 1000m

Therefore it covers 1000m

$ItzDopeGirl$❣

Answer 2

ANSWER :

Given :

▪ Intial velocity of car = zero (i.e. rest)

▪ Acceleration of car = 5m/s^2

▪ Time interval = 20s

To Find :

▪ Distance covered by car in the given interval of time.

Concept :

▪ Since acceleration is constant throughout the whole journey, we can apply equation of kinenatics directly.

▪ Third equation of kinematics is given by

☞ S = ut + (1/2)at^2

Calculation :

✳ initial speed = 0

✒ S = (1/2)at^2

✒ S = 0.5 × 5 × (20)^2

✒ S = 0.5 × 5 × 400

✒ S = 1000m = 1km