a racing car has a uniform acceleration of 8ms² what distance will it cover in 10 second after start
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Answer:
distance=400 m
Explanation:
given acceleration a=8 m/s²
time t=10 s
initial velocity u=0 m/s[since it is mentioned in the question as after start]
Use the second equation of motion
s=ut+1/2at²
s=0+1/2×8×10²
s=0+4×100
s=0+400
s=400 m
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