Question

A racing car has a uniform acceleration of the 4m s-2.What distance will it cover in 10s after start? ​

Answer 1

Answer:

200 m

Explanation:

As per the provided information in the given question, we have :

• Acceleration (a) = 4 m/s²
• Initial velocity (u) = 0 (As it starts from rest)
• Time taken (t) = 10 s

We are asked to calculate distance covered by it in 10 s.

By using the second equation of motion,

⇒ s = ut + ½at²

• s denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

⇒ s = 0(10) + ½ × 4 × (10)²

⇒ s = ½ × 4 × 100

⇒ s = 1 × 2 × 100

⇒ s = 200 m

∴ Distance covered in 10 seconds is 200 m.

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More Information :

First equation of motion :

$\longmapsto\rm {v = u + at }$

Second equation of motion :

$\longmapsto\rm {s = ut + \dfrac{1}{2}at^2 }$

Third equation of motion :

$\longmapsto\rm {v^2 - u^2 = 2as}$

Where,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance