Question

A racing car has a uniform acceleration on has 4 metre per second then what distance will it cover in 10 second find

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Answer 1

➠Answer:

The distance covered is 200 m.

Given :

Uniform acceleration = 4 m/s²

Initial velocity = 0 m/s

Time = 10 sec

➠Solution :

• a = 4 m/s²
• t = 10 s
• u = 0 m/s

Find the velocity after 10 sec.

⇒ v = u + at

⇒ v = 0 m/s + 4 m/s² × 10 s

⇒ v = 40 m/s

Using relation → v² - u² = 2as

a = 4 m/s²

u = 0 m/s

v = 40 m/s

⇒ (40)² - (0)² = 2(4)(s)

⇒ 1600 - 0 = 8s

⇒ 1600 = 8s

⇒ s = 1600/8

⇒ 200 m

Therefore, the distance covered is 200 m.

Answer 2

$\huge\underline\bold\red{AnswEr}$

Uniform acceleration a = 4 m/s²

Initial velocity u= 0 m/s

Time t = 10 sec.

Velocity v after 10 sec= u + a t = 0 m/s + 4 m/s² × 10 s =40 m/s.

☞︎︎︎We shall calculate the distance covered by all possible methods

☞︎︎︎Using Average Velocity:

Initial velocity u= 0 m/s

Final velocity v= 40 m/s

Average velocity= ½( u +v) = ½ ( 0+40)= 20 m/s

Time= 10 s

Distance covered in 10 s= av. vel. × time= 20m/s × 10s = 200 m

☞︎︎︎Using the relation s = u t+ ½ a t²

u = 0 m/s, a = 4 m/s², t= 10 sec.

s = 0×10 + ½ 4× 10² = 200 m

☞︎︎︎Using the relation v² - u² = 2 a s,

u = 0 m/s, v= 40 m/s, a= 4 m/s²

s = 1/2 a ( v² - u²)= 1/2×4 ( 40² - 0²) = 1/8(1600–0)= 1600/8= 200 m.

☞︎︎︎So all relations give the same results as it should.