Question

A racing car has a unifrom acceleration
Of 4m s^-2. What distance will it cover in 10 s after start ?

Answer 1

GIVEN:

• Acceleration (a) = 4 m/s²
• Time taken (t) = 10 seconds
• Initial Velocity (u) = 0 m/s

TO FIND:

• What is the distance covered by the car?

SOLUTION:

Let the distance covered by the car be 's' m

We know that the formula for finding the distance covered by the car is:-

$\large\bf{\star \: s = ut + \dfrac{1}{2} at^2 \: \star}$

According to question:-

On putting the given values in the formula,we get

$\rm{\dashrightarrow s = 0 \times 10 + \dfrac{1}{2} \times 4 \times (10)^2 }$

$\rm{\dashrightarrow s = 0 + \dfrac{1}{\cancel{2}} \times \cancel{4} \times 100 }$

$\rm{\dashrightarrow s = 2 \times 100 }$

$\bf{\star \: s = 200 \: m \: \star}$

❝ Hence, the distance covered by the car is 200 m ❞

______________________

VERIFICATION:

$\rm{\dashrightarrow 200 = 0 \times 10 + \dfrac{1}{2} \times 4 \times (10)^2 }$

$\rm{\dashrightarrow 200 = 0 + \dfrac{1}{\cancel{2}} \times \cancel{4} \times 100 }$

$\rm{\dashrightarrow 200 = 2 \times 100 }$

$\bf{\star \: 200 = 200 \: m \: \star}$

VERIFIED....

Answer 2

Given,

• Initial Velocity (u) - 0
• Uniform Acceleration (a) - 4m/s²
• Time (t) - 10 Second

To Find,

• What Distance will it Cover in 10 second after Start

Solution :

$\implies$ We Know that :

$\bigstar \boxed{\orange{\sf{s = ut + \dfrac{1}{2}at^{2}}}}$

║Here,

• s = Distance
• u = Initial Velocity
• t = Time
• a = Acceleration ║

Now Put the Value in this Equation :

$\longrightarrow \sf{s = 0 \times 10 + \dfrac{1}{2} \times 4 \times (10)^{2}}$

$\longrightarrow \sf{s = \dfrac{1}{2} \times 4 \times 100}$

$\longrightarrow \sf{s = 2 \times 100}$

$\longrightarrow \boxed{\sf{s = 200m}}$

Therefore,

$\mapsto \boxed{\mathfrak{\pink{Distance\:it\:will\:cover\:in\:10s\:after\:start\:is\:200m}}}$

$\rule{200}2$