Physics, asked by rakeshtamilan2206200, 10 months ago

A racing car has an acceleration of 4 m/s2

. What distance will it cover in 20 seconds after

start?​

Answers

Answered by kiyara01
28

Answer:

hope this attachment will help you

mark as brainlest answer please

Attachments:
Answered by BrainlyConqueror0901
34

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Distance\:travel=800\:m}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:  \implies  Acceleration(a) =  4 \: m/ {s}^{2} \\  \\  \tt:  \implies Time(t) =20\: m \\  \\ \red{\underline \bold{To \: Find :}} \\  \tt:  \implies Distance(s)= ?

• According to given question :

 \tt \circ \: Initial \: velocity  = 0 \: m/s\\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies  s  = ut+\frac{1}{2}at^{2}\\  \\  \tt:  \implies  a=0\times 20+ \frac{1}{2} \times 4 \times 20^{2} \\  \\  \tt:  \implies s= 2\times 400 \\  \\  \green{\tt:  \implies s =  800\:m}   \\  \\   \blue{\bold{Some \: related \: formula : }} \\  \orange{ \tt \circ \: v = u + at} \\  \\ \orange{ \tt \circ \:  {v}^{2} =  {u}^{2}  + 2as}

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