A racing car has an acceleration of 4m/s square .what distance it will cover in 20 sec after the start
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Answered by
0
A= 4m/s^2
T=20sec
U=0m/s
V=u+at
=0+4*20
=80
2as=v^2-u^2
S=v^2-u^2\2a
S=80^2-0^2\2*4
S=20m
T=20sec
U=0m/s
V=u+at
=0+4*20
=80
2as=v^2-u^2
S=v^2-u^2\2a
S=80^2-0^2\2*4
S=20m
Answered by
11
Refer https://brainly.in/question/4391450.
Take t = 20 instead of 10. You get the answer 800 m.
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