A racing car has uniform acceleration of 10ms raised to -2.What distance will it cover in 20 seconds after start
Answers
Answered by
3
Answer:
2000 metres
Explanation:
Given :
- Acceleration of the racing car = a = 10 m/s²
- Time taken = t = 20 seconds
- Initial velocity = u = 0 m/s
To find :
- Distance covered by the racing car after start
Using the second equation of motion :
S=ut+½×at²
S=0×20+½×10×20²
S=0+5×400
S=2000 metres
The distance covered by the racing car after start is equal to 2000 metres or 2 kilometres
Answered by
202
Given :-
- Initial velocity (u) of car =0m/s
- Acceleration of car (a) =10m/s²
- Time taken (t) =20s
To Find:-
- .Distance covered by car.
Solution :-
By using 2nd equation of motions
➦ s = ut+1/2at²
➭ s = 0×20+1/2×10×20²
➭ s = 5 × 400
➭ s = 2000m
➭ s = 2000/1000= 2km
∴ The distance covered by car is 2km
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