Question

A racing car has uniform acceleration of 4 m/s square . what distance will it cover in 10 second after start ? ​

Answer 1

Explanation:

acceleration is uniform being 4 m/s ^2.

Hence a = 4 m/s^2

Time,t = 10 seconds

Body starts from rest so u = 0 m/s

We know that when u = 0 m/ s

Distance , s = 1/2 a(t)^2

s = 1/2 × 4× 10 ×10

s= 200 m

Hope it helps u.....

Answer 2

Given :

⟶ Initial velocity = zero

⟶ Acceleration = 4m/s²

⟶ Time interval = 10s

To Find :

➳ Distance covered by car in the given interval if time.

Concept :

⇒ Since, acceleration has said to be constant throughout the motion, we can easily apply equation of kinematics to solve this question.

⇒ Second eq. of kinematics :

• S = ut + 1/2(at²)

where,

• s denotes distance
• u denotes initial velocity
• a denotes acceleration
• t denotes time

Calculation :

$\longrightarrow\sf\:S=ut+\dfrac{1}{2}at^2\\ \\ \longrightarrow\sf\:S=(0\times 10)+\dfrac{1}{2}(4\times 10^2)\\ \\ \longrightarrow\sf\:S=2\times 100\\ \\ \longrightarrow\boxed{\bf{S=200m}}$