Question

A racing car has uniform acceleration of 4 m/s square what distance Will it cover in 10 seconds after the start?

Answer 1

S = ut + 1/2at^2
u =0
S = 1/2at^2
S = 1/2* 4* 10*10
S = 200m

Answer 2

ANSWER:-

Known Terms:-

u = Initial Velocity

a = Acceleration

t = Time

s = Distance

Given:-

Initial Velocity of  car, u = 0 ms-1

Acceleration of car, a = 4 m s-2

Time taken by the car, t = 10 s

To Find:-

Distance (s)

Solution:-

Here we have to find the distance

so,

Here, we use 3rd equation of motion that is  s = ut + 1/2at²

⇒ s = ut + at²

⇒ s = 0 + () × 4 × 10²

⇒ s = 0 + () × 4 × 10 × 10

⇒ s = () × 400 m

⇒ s = 200 m

The distance cover in 10 s after start is 200 m.

THANKS!!!