Question

A racing car has uniform acceleration of 4 ms −2
. What distance will it cover in 10 s after start?

Answer 1

Correct Question :-

A racing car has uniform acceleration of 4ms^-2.What distance will it cover in 10s after start?

Answer :-

200m

Explanation:

Given :

Acceleration,a = 4m/s^2

Initial velocity,u = 0

Time taken = 10s

To Find :

Distance,s = ?

Solution :

According to the second law of motion,

$\sf{}\sf{}\bf{s=ut+\dfrac{1}{2}at^2}$

Put their values and solve for “s”

$\sf{}\implies s=0\times 10s+\dfrac{1}{2}\times 4m/s^2 \times(10s)^2+\dfrac{1}{2}at^2$

$\sf{}\implies s=0+\dfrac{1}{2}\times 4m/s^2 \times100s^2$

$\sf{}\implies s=\dfrac{1}{1}\times 2m/s^2 \times100s^2$

$\sf{}\therefore s=200m$

Therefore,distance travelled by the car is equal to 200m

Answer 2

Answer: May my answer helps you.