a racing car has uniform acceleration of 4m/s what distance will it cover in 10s after start
Harshit644:
200 m by using 2 equation of motion
Answers
Answered by
13
a=4ms
4ms=velocity/10
velocity =40
speed =D/t
40=D/10
ditance is 400
4ms=velocity/10
velocity =40
speed =D/t
40=D/10
ditance is 400
Answered by
13
Here initial velocity=u
final velocity=v
acceleration=a
time=t
u=0
a=4
t=10
use the first equation of motion i.e -v=u+at
v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2
2*4*s=1600
s+1600/8=200m
final velocity=v
acceleration=a
time=t
u=0
a=4
t=10
use the first equation of motion i.e -v=u+at
v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2
2*4*s=1600
s+1600/8=200m
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