Question

A racing car has uniform acceleration of 4m/s2. How much distance will it cover in 1min after the start and what will be the final velocity of the car after 20sec??

Answer 1

Answer:

a) distance = 7200 m

b) final velocity = 80 m/s

Explanation:

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Answer 2

Answer:

80m/s is velocity

and distance is 7200 m

Explanation:

initial velocity(u) = 0m/s

acceleration(a) = 4m/s2

time(t) = 20s

now a = v-u/t

=> 4 = v - 0 /20

=> 4 = v / 20

=> 4 × 20 = v

=> 80 = v

or v = 80

therefore final velocity is 80m/s

for distance covered we ose the equation

s = ut + 1/2at2

=0×60 + 1/2×4×60×60

=2×3600

=7200

therefore distance travelled is 7200m