Question

A racing car has uniform acceleration of 4m/s2 what distance it covers in 10 seconds after it starts

Answer 1

here initial velocity=u
final velocity=v
acceleration=a
time=t

u=0
a=4
t=10
use the first equation of motion i.e -v=u+at

v=0+40
v=40m/s
now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

s+1600/8=200m

Answer 2

s=?
u=0m/s2
a=4m/s2
t=10s
Using 2nd law of motion,
s=ut+at2/2
s=0(10)+4(10)2/2
=0+1600/2
=800m