Question

a racing car has uniform acceleration of 4m/s² what distance will it cover in 10 sec.​

Answer 1

Answer:

200 m

Explanation:

Currently you have not mentioned wether it was at rest or moving. So, I am considering it was at rest.

A.T.Q.

u = 0 m/sec.

v = u + at (Using 1st law of motion)

= 0 + 4×10

= 40m/sec.

Using Newton's 3rd law of motion,

v^2 - u^2 = 2as

(40)^2 - (0)^2 = 2 × 4 × s

1600 = 8s

s = 200m

Hope it helps, Plz mark me the brainliast.

Answer 2

Answer:

Here's ur answer,

• As per the question..

acc. (a) = 4m/s²

time (t) = 10s

initial velocity (u) = 0m/s

distance (s) = ?¿

• By using eq. of motion.,

s = ut + ½ at²

s = 0(10) + ½(4)(10)(10)

s = 0 + 2(100)

s = 200m

Distance travelled by the racing car in 10s is 200m.

Thanks !