Question

A racing car has uniform acceleration of 4ms what distance will it covers in10 sec after the start

Answer 1

LET INITIAL VELOCITY BE 0

acceleration = 4m/s

time = 10 seconds

s= ut+1/2at^2

s= 0 x 10 + 1/2 x4 x 100

s = 0 + 2 x 100

s = 200 m

Answer 2

As we know that by 2 equation of motion s=ut+1/2at^2

Here u=0m/s(after the start) acc^n=4m/s^2

T=10s

So s= 0*10+1/2*4(10)^2

S=0+2(100)

S=200m

So the distance coveres is equal to 200 m