Question

a racing car initially at rest ,accelerates at a uniform rate of 5•5m/S2 for 10 s. calculate 1) the distance cover by the racing car from start , and 2) the final velocity in Km/h .​

Answer 1

Answer:

$u = 0 \: m \div s \\ a = 55 \div 10 \: m \div s \\ t = 10s \\ v = 55m \div s \\ s = 275m \\ v \: \: in \: \: km \div h \\ 198 \: km \div h$

Explanation:

please mark me the brainliest

Answer 2

Answer:

Solution:

u=0m/s

a= 5.5m/s2

t= 10s

v=?

1. distance covered

we know that s= ut+1/2 at2

s= 0x 10 + 1/2 x 5.5 x 10 x 10

s= 0 + 1/2 x 55 x 10

s= 1/2 x 550

s= 275 m

2. Final velocity of car in km/h

v= u + at

v= 0+ 5.5 x 10

v= 5.5 x 10

v= 55 m/s

55m/s in km/h:

we know that to convert m/s to km/h we multiply the number with 18/5

55 x 18/5 = 198km/h

Hope my answer helps!