Question

A racing car initially at rest, accelerates at a uniform rate of 5.5m/s² for 10 s. Calculate
for the distance covered by the racing car from start and the final velocity in km/h.





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Answer 1

Answer:

Distance covered by racing car from rest

S

=ut+1/2at^2

S

=

(

0 m/s × 10 s

)

+

(

1

2

×

5.5 m/s

2

×

(

10 s

)

2

)

=

275 m

2. Final Velocity

v = u + at

v

=

0 m/s

+

(

5.5 m/s

2

×

10 s

)

=

55 m/s

55

m

s

×

3600

s

1 hour

×

1 km

1000

m

=

198 km/hr

here is your answer dear..

have a nice day..

Answer 2

Answer:

1. Distance covered by racing car from rest

$S= ut+ \frac{1}{2}at^{2}$

S =(0 m/s × 10 s)+$(\frac{1}{2}$ ×$5.5m/s^{2}$×$(10s)^{2}$$)$=275m

2. Final Velocity

v = u + at

v  = 0 m/s + (  5.5 m/s  ² × 10 s ) = 55 m/s

$\frac{55m}{s}$×$\frac{3600s} {1 hour}$×$\frac{1 km}{1000m}$=198km/hr