Question

A racing car, initially at rest, picks up a velocity of {180kmh}^{ - 1} in 4.5s .Calculate 1) acceleration 2) distance covered by car.

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Answer 1

Answer:

Acceleration and distance are covered in a racing car

Answer 2

Given:-

$u = 0$

$v = {180kmh}^{ - 1 } = {50ms}^{ - 1}$

$t = 4.5s \: \: \:$

a = ? , S = ?

(i)Applying:-

${v} = {u} + at$

$50 = 0 + a \times 4.5$

$a = \frac{50}{4.5 } = {11.11ms}^{ - 2}$

(ii) Applying:-

${v}^{2} - {u}^{2} = 2as$

${(50)}^{2} - {(0)}^{2} = 2 \times \frac{50}{4.5} \times s$

$s = \frac{50 \times 50 \times 4.5}{2 \times 50}$

$= 11.25m$

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