Question

A radar sends radiowaves of frequency v towards an
aeroplane moving with velocity vₐ. A change Dn is observed
in the frequency of reflected waves which is higher than
original frequency. The velocity of aeroplane is (vₐ << c)
(a)c ∆v/v
(b)2c∆v/v
(c)c∆v/2v
(d) ∆v/2cv

Answer 1

Answer:

Here's your answer

Explanation:

Since through first polarizer, intensity will get halved. Hence, light incident on second polarizer will have intensity

2

I Through the second polarizer, intensity will decrease by a factor of cos

2

θ. Hence intensity after passing through second polariser is:

2

I

cos

2

θ=

2

I

cos

2

(45

0

)=

4

I

Answer 2

Explanation:

option c is correct