Chemistry, asked by pratikshabhardwaj27, 7 months ago

a radiation of wavelength 4650 A. calculate it's frequency and wavenumber

Answers

Answered by makwanachirayu753
10

Explanation:

lambda=4650 Angstroms=0.465×10^(-6)

frequency=speed of light/wavelength

Hence frequency=3×10^(8)/0.465×10^(-6)

So frequency=6.45×10^14 Hz

Now wave number=inverse of wavelength

So wave number= 1/0.465×10^(-6)

Hence wave number=2.15×10^6 meter^(-1)

THANKS

Answered by nishagupta89853
1

Answer:

lambda=4650 Angstroms=0.465×10^(-6)

frequency=speed of light/wavelength

Hence frequency=3×10^(8)/0.465×10^(-6)

So frequency=6.45×10^14 Hz

Now wave number=inverse of wavelength

So wave number= 1/0.465×10^(-6)

Hence wave number=2.15×10^6 meter^(-1)

Explanation:

hope it helps you

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