a radiation of wavelength 4650 A. calculate it's frequency and wavenumber
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Answered by
10
Explanation:
lambda=4650 Angstroms=0.465×10^(-6)
frequency=speed of light/wavelength
Hence frequency=3×10^(8)/0.465×10^(-6)
So frequency=6.45×10^14 Hz
Now wave number=inverse of wavelength
So wave number= 1/0.465×10^(-6)
Hence wave number=2.15×10^6 meter^(-1)
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Answered by
1
Answer:
lambda=4650 Angstroms=0.465×10^(-6)
frequency=speed of light/wavelength
Hence frequency=3×10^(8)/0.465×10^(-6)
So frequency=6.45×10^14 Hz
Now wave number=inverse of wavelength
So wave number= 1/0.465×10^(-6)
Hence wave number=2.15×10^6 meter^(-1)
Explanation:
hope it helps you
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