Question

A radio station broadcast on a frequency of 980 kHz. Calculate the wavelength of the electromagnetic radiation.

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Answer 1

AnswEr :

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⠀⠀⠀$\bullet$⠀Frequency [v] = 980 kHz

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$\implies\sf 980 \times 10^{3} Hz$

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⠀⠀⠀⠀⠀⠀⠀⠀Using Formula :

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$\star\: \: \boxed{\frak{ v = \dfrac{c}{\lambda}}}$

$\qquad\qquad\quad\underline{\sf{Substituting \ Values \ :}}$

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⠀⠀⠀⠀⠀Now Finding wavelength : ⠀⠀⠀⠀

$\implies\sf v = \dfrac{ 3 \times 10^{8} ms^{-1}}{980 \times 10^{3}} \\\\\\\implies\sf \dfrac{3}{98} \times 10^{4} \\\\\\\implies\boxed{\frak{\purple{306 \ m}}}$

Hence, wavelength of the electromagnetic radiation is 306 m.

Answer 2

Given:

• v= frequency= 980kHz

Need to find:

• The wavelength= $\lambda$=?

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Solution:

980 kHz

=980 ×1000 Hz

C= $3× 10^{8}$

Now we know:

$\red{\bold{C = \nu \: \lambda \: }}$

Substituting the values:

$3 \times {10}^{8} = 980 \times 1000 \: \times \lambda$

$\implies \: \lambda \: = \dfrac{3 \times {10}^{8} }{980 \times 1000}$

$\implies \lambda = \dfrac{3 \times {10}^{8 - 3} }{980} m$

$\implies \: \lambda = \dfrac{3 \times {10}^{5} }{980} m$

$\implies \: \lambda = 0.00306 \times {10}^{5} m$

$\implies \: \lambda = 3.06 \times {10}^{2} m$

$\red{\boxed{ \therefore\: \lambda \: = 306 m}}$