Question

a radio station play "Assam Sangeet" once every two days.another radio station play the same song once every three days.how many times in 30 days will both the radio station play the same song on the same day​

Answer 1

The song will be played 5 times in 30 days.

To do this, we need to find the common factors of 2 and 3.

• The LCM of 2 and 3 is 6.
• So, every number divisible by 6 is divisible by both 2 and 3.
• Multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48.......
• Only 5 numbers -- 6, 12, 18, 24, 30 are less than or equal to 30.

Hence, the song will be played by both radio stations on the 6th, 12th, 18th, 24th and on the 30th day.

Answer 2

Answer:

5 times

Step-by-step explanation:

A radio station plays assam sangeet 1 time in 2 days.

Another radio station plays same song 1 time in 3 days .

LCM(2,3)=2\times 32×3

LCM(2,3)=6=6

On 6th days both radio station plays the same song .

Total number of days=30

Therefore, both radio station plays same song by taking gap of 6 days .

It means

6,12,18,24,30

Total number of days in 30 days on which both radio station plays same =5